Solving Friction Problems

Braking acts to slow an object, so acceleration of the truck and the cartons is in the opposite direction as the velocity.

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A delivery truck with two stacked cartons in the back brakes quickly.

/2μg from v=u at or t=v/μg Question 2A horizontal force of F N is necessary to just hold a block stationary against a wall. F/μ d none of these Solution 2 Let W be the weight Reaction force=F Weight downward=W weight Upward=frictional force=μr=μF For no movement weight Upward=Weight downward W=μF Question 3. If the coefficient of friction between the chain and the table top is μ. What is the shortest distance and shortest time in which the block can be stopped if μ is coefficient of friction a.v/2μg from v=u at or t=v/μg Question 8A horizontal force of F N is necessary to just hold a block stationary against a wall. F/μ d none of these Solution 8 Let W be the weight Reaction force=F Weight downward=W weight Upward=frictional force=μr=μF For no movement weight Upward=Weight downward W=μF Note to our visitors :- Thanks for visiting our website.

The coefficient of friction between the block and the wall is μ. A body is sliding down a rough inclined plane of angle of inclination θ for which coefficient of friction varies with distance y as μ(y)=Ky where K is constant. what is the maximum length of the chain that can hang over the edge of the table without disturbing the rest of the chain on table.? The coefficient of friction between the block and the wall is μ. DISCLOSURE: THIS PAGE MAY CONTAIN AFFILIATE LINKS, MEANING I GET A COMMISSION IF YOU DECIDE TO MAKE A PURCHASE THROUGH MY LINKS, AT NO COST TO YOU.

Do notice that there is a forward force on the lower carton in addition to the frictional force acting backwards on it, and so you do need to justify to yourself that it doesn’t affect that answer.

Regardless, this problem is provided as a sample because it illustrates how you would apply Newton’s 2nd and 3rd Law in a wide variety of problems that you might be asked to solve on your homework, and so it is worth looking at the mathematical analysis. At the start of the problem, the truck and both cartons are traveling forward.Here y is the distance moved by the body down the plane. The coefficient of kinetic friction between the objects and incline is given by. 1/(1-n Question 5A uniform chain of length L is lying on the horizontal surface of a table. A force is applied to the body to make it just slide with a constant acceleration which is a. 3g/4 d g Solution 6 Minimum force with which body will just move=μmg or a=g/4 Question 7 A block of m Ass M is moving with a velocity v on straight surface.If there was no kinetic friction, any object that you nudge (for example, a toy car) would never stop moving, as, according to Newton's first law, no force would act on it, so it would keep on going with a constant velocity.Even though the formula is the same for static and kinetic friction, you need to remember that the coefficients of friction are different.It is true that the bottom carton feels the weight of the top carton.However, that information is transmitted through the force of contact, n.If you include a force by the brakes in your FBDs for the cartons, you will double count the retarding force.The free body diagram is a sketch of the Braking acts to slow an object, so acceleration of the truck and the cartons is in the opposite direction as the velocity.As the truck brakes, each carton will continue to move forward at a constant velocity due to inertia unless there is a net force (such as friction) acting on it. The problem statement tells you that there is friction both between the bottom carton and the truck and between the two cartons.Recall that friction acts to oppose sliding motion.